Number Theory

Weyl's Equidistribution Theorem

Weyl's criterion lets us test uniform distribution by checking exponential sums. We will prove the equivalence between this test, interval counts, and averages of Riemann-integrable functions. A sequence of real numbers \(x_1, x_2, \cdots\) is said to be equidistributed (mod 1) if for every sub-interval \((a,b)\subset [0,1]\), we have

\[ \lim_{N\to \infty}\frac{|\{1\leq n\leq N:\; \langle x_n \rangle\in (a,b)\}|}{N} = b-a \]

where \(\langle x \rangle\) denotes the fractional part of \(x\). Weyl's equidistribution criterion states that the following statements are equivalent:

  1. \(x_1, x_2, \cdots\) are equidistributed (mod 1).
  2. For each non-zero integer \(k\), we have

    \[ \lim_{N\to\infty}\frac{1}{N}\sum_{n=1}^N e^{2\pi i k x_n}=0 \]
  3. For each Riemann integrable function \(f:[0,1]\to\mathbb{C}\), we have

    \[ \lim_{N\to \infty}\frac{1}{N}\sum_{n=1}^N f(\langle x_n \rangle) = \int_0^1 f(x) dx \]

Proof: (1) ⇒ (3)

Let \(I=[a,b)\subseteq [0,1]\) and note that

\[ \frac{|\{1 \leq n \leq N: \langle x_n \rangle\in [a,b) \}|}{N}=\frac{1}{N}\sum_{n=1}^N \chi_{[a,b)}(\langle x_n \rangle) \]

where \(\chi_{[a,b)}(x)\) equals 1 if \(x\in [a,b)\) and 0 otherwise. This shows that (3) holds for the case when \(f\) is a characteristic function. Now, let \(\lambda_1, \lambda_2\in \mathbb{R}\) and \(f_1\), \(f_2\) be functions for which (3) holds. Then,

\[ \begin{aligned}\lim_{N\to \infty}\frac{1}{N}\sum_{n=1}^N (\lambda_1 f_1 + \lambda_2 f_2)(\langle x_n \rangle) &= \lim_{N\to \infty} \frac{\lambda_1}{N}\sum_{n=1}^N f_1(\langle x_n\rangle) + \lim_{N\to \infty}\frac{\lambda_2}{N}\sum_{n=1}^Nf_2(\langle x_n\rangle) \\ &= \lambda_1\int_0^1 f_1(x) dx + \lambda_2 \int_0^1 f_2(x) dx \\ &= \int_0^1 (\lambda_1 f_1 + \lambda_2 f_2)(x) dx\end{aligned} \]

Thus, (3) holds for all linear combinations of characteristic functions of subintervals of \([0,1]\).

Now, let \(f:[0,1]\to \mathbb{R}\) be an integrable function, and let \(\epsilon >0\). Choose step functions \(f_1\) and \(f_2\) such that:

  • \(f_1\leq f\leq f_2\) pointwise
  • \(\int_0^1 (f_2(x)-f_1(x))dx < \frac{\epsilon}{2}\)
  • There exists \(N_0\) such that \(\left|\int_0^1 f_1(x)dx - \frac{1}{N}\sum_{n=1}^N f_1(\langle x_n\rangle) \right| < \frac{\epsilon}{2}\) and \(\left|\int_0^1 f_2(x)dx - \frac{1}{N}\sum_{n=1}^N f_2(\langle x_n\rangle) \right| < \frac{\epsilon}{2}\) for all \(N\geq N_0\)

It follows that for \(N\geq N_0\),

\[ \begin{aligned} \int_0^1 f(x) dx - \frac{1}{N}\sum_{n=1}^N f(\langle x_n\rangle) &\leq \int_0^1 f(x) dx - \frac{1}{N}\sum_{n=1}^N f_1(\langle x_n\rangle) \\ &< \int_0^1 f(x) dx -\int_0^1 f_1(x) dx +\frac{\epsilon}{2} \\ &< \int_0^1 (f_2(x)-f_1(x)) dx + \frac{\epsilon}{2} \\ &< \epsilon \end{aligned} \]

In a similar way, we can prove that

\[ \int_0^1 f(x) dx - \frac{1}{N}\sum_{n=1}^N f(\langle x_n\rangle) > -\epsilon \quad \forall\; N\geq N_0 \]

Therefore, we have

\[ \left|\int_0^1 f(x) dx - \frac{1}{N}\sum_{n=1}^N f(\langle x_n\rangle) \right| < \epsilon \quad \forall\; N\geq N_0 \]

To see that (3) holds when \(f\) is complex valued, we need only consider the real and imaginary parts separately.

(2) ⇒ (3)

First let \(f\) be continuous and \(1\)-periodic. Trigonometric polynomials uniformly approximate such functions on the circle. For any \(\epsilon>0\), choose

\[ p(x)=\sum_{|k|\leq m}c_k e^{2\pi i kx},\qquad \|f-p\|_\infty<\epsilon. \]

By (2), the average of \(p(x_n)\) tends to its constant coefficient \(c_0=\int_0^1p(x)\,dx\). Thus

\[ \limsup_{N\to\infty}\left|\frac1N\sum_{n=1}^N f(\langle x_n\rangle)-\int_0^1 f(x)\,dx\right|\leq2\epsilon. \]

Letting \(\epsilon\to0\) proves the assertion for continuous periodic \(f\).

To pass to interval indicators, fix an arc \(I\) of the circle. For any \(\epsilon>0\), choose continuous periodic functions \(g_-\) and \(g_+\), with short linear ramps near the endpoints, such that

\[ g_-\leq\chi_I\leq g_+,\qquad \int_0^1(g_+-g_-)\,dx<\epsilon. \]

Their integrals bracket the length of \(I\). Applying the result just proved to \(g_-\) and \(g_+\) squeezes the limiting interval frequency to that length. The same construction with a small neighborhood of a single point shows that endpoint visits have density zero, so the choice of open, closed, or half-open endpoints does not affect the result. This proves (1). The argument in (1) ⇒ (3) now extends the conclusion to all Riemann-integrable functions.

Periodicity is essential in the first approximation step: a continuous function on \([0,1]\) whose endpoint values differ cannot be uniformly approximated there by trigonometric polynomials.

The implications (3) ⇒ (1) and (3) ⇒ (2) are obvious.

References

  • Hannigan-Daley, Brad. Equidistribution and Weyl’s criterion. Retrieved from http://individual.utoronto.ca/hannigandaley/equidistribution.pdf. Accessed 5 Feb. 2020.
  • Stein, Elias M. and Shakarchi, Rami. Fourier Analysis: An Introduction. Princeton University Press, 2003
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